Add part 3d solution
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@ -152,3 +152,8 @@ SELECT companyName || Company.stockSymbol AS CruiseCompany, Cruise.cruiseName, R
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NATURAL JOIN Company
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WHERE Cruise.Days >= 10 AND Reservation.travelDate >= '1-JAN-2019'
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ORDER BY Cruise.cruiseName ASC, Reservation.travelDate ASC;
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-- 3d
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SELECT travelAgent.firstName, travelAgent.lastName, travelAgent.title FROM travelAgent
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LEFT JOIN Reservation ON travelAgent.travelAgentID = Reservation.travelAgentID
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WHERE Reservation.travelAgentID IS NULL;
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